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Sr+ + H2O ↔ SrOH+ + H equilibrium was studied spectrophotometrically. This reaction occurs in natural gas combustion products. Its enthalpy ΔrH ○(0) = 61.4 ± 2.8 kJ/mol and bond energy D 0(Sr+-OH) = 432.6 ± 2.8 kJ/mol were determined using the third law of thermodynamics. The experimental data on this reaction obtained earlier in hydrogen flames, ΔrH ○(0) = 55.3 ± 10.6 and D 0(Sr+-OH) = 438.7 ± 10.6 kJ/mol, were interpreted anew. The D 0(Sr+-OH) = 432.8 ± 2.7 kJ/mol value was eventually obtained.

Authors:   V. N. Belyaev, N. L. Lebedeva
Journal:   Russian Journal of Physical Chemistry A
Year:   2012
DOI:   10.1134/S0036024412060052
Publication date:   05-05-2012

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