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# Transition dipole moment

The Transition dipole moment or Transition moment, usually denoted $\scriptstyle{\mathbf{d}_{nm}}$ for a transition between an initial state, $\scriptstyle{m}$, and a final state, $\scriptstyle{n}$, is the electric dipole moment associated with the transition between the two states. In general the transition dipole moment is a complex vector quantity that includes the phase factors associated with the two states. Its direction gives the polarization of the transition, which determines how the system will interact with an electromagnetic wave of a given polarization, while the square of the magnitude gives the strength of the interaction due to the distribution of charge within the system. The SI unit of the transition dipole moment is the Coulomb.meter (Cm); a more conveniently sized unit is the Debye (D).

## Definition

The transition dipole moment for the $\scriptstyle{m\, \rightarrow\, n}$ transition is given by the relevant off-diagonal element of the dipole matrix, which can be calculated from an integral taken over the product of the wavefunctions of the initial and final states of the transition, and the dipole moment operator,

$\mathbf{\hat{d}} = e\left(\sum_i x_i, \sum_i y_i, \sum_i z_i\right)$,

where the summations are over the positions of the electrons in the system. Giving the transition dipole moment:

$\mathbf{d}_{nm} = \int \Psi^*_n \,\, \mathbf{\hat{d}} \,\, \Psi_m \, d^3r = \langle\Psi_n|\,\mathbf{\hat{d}}\,|\Psi_m\rangle$,

where the integral is, in principle over all space, but can be restricted to the region in which the initial and final state wavefunctions are non-negligible.

## Analogy with a classical dipole

Main article: Electric dipole moment

A basic, phenomenological understanding of the transition dipole moment can be obtained by analogy with a classical dipole. While the comparison can be very useful, care must be taken to ensure that one does not fall into the trap of assuming they are the same.

In the case of two classical point charges, $\scriptstyle{+q}$ and $\scriptstyle{-q}$, with a displacement vector, $\scriptstyle{\mathbf{r}}$, pointing from the negative charge to the positive charge, the electric dipole moment is given by

$\mathbf{p} = q\mathbf{r}$.

In the presence of an electric field, such as that due to an electromagnetic wave, the two charges will experience a force in opposite directions, leading to a net torque on the dipole. The magnitude of the torque is proportional to the magnitude of the charge, the separation and varies with the relative angles of the field and the dipole,

$|\mathbf{\tau}| = |q\mathbf{r}||\mathbf{E}|\sin\theta$.

Similarly, the coupling between an electromagnetic wave and an atomic transition with transition dipole moment $\scriptstyle{\mathbf{d}_{nm}}$, depends on the charge distribution within the atom, the strength of the electric field, and the relative polarizations of the field and the transition. In addition, the transition dipole moment depends on the geometries and relative phases of the initial and final states.

## Origin

When an atom or molecule interacts with an electromagnetic wave of frequency $\scriptstyle{\omega}$, it can undergo a transition to a higher energy state by absorbing a photon or a lower energy state by emitting a photon, provided that the energy difference between the initial and final states $\scriptstyle{(\Delta E)}$ is the same as the photon energy $\scriptstyle{(\hbar\omega)}$. The presence of the electromagnetic field can induce an oscillating electric dipole moment, referred to as the transition dipole moment. If the charge, $\scriptstyle{e}$, is omitted one obtains $\scriptstyle{\mathbf{R}_\alpha}$ as used in oscillator strength.

## Applications

The transition dipole moment is useful for determining if transitions are allowed. For example, the transition from a bonding $\scriptstyle{\pi}$ orbital to an antibonding $\scriptstyle{\pi^*}$ orbital is allowed because the integral defining the transition dipole moment is nonzero. Such a transition occurs between an even and an odd orbital; the dipole operator is an odd function of $\scriptstyle{\mathbf{r}}$, hence the integrand is an even function. The integral of an odd function over symmetric limits returns a value of zero, while for an even function this is not necessarily the case.

## References

IUPAC compendium of Chemical Terminology. IUPAC (1997). Retrieved on 2007-01-15.